Answer :
Answer: The mass of methane that will dissolve is 0.7008 grams
Explanation:
To calculate the molar solubility, we use the equation given by Henry's law, which is:
[tex]C_{CH_4}=K_H\times p_{CH_4}[/tex]
where,
[tex]K_H[/tex] = Henry's constant = [tex]9.88\times 10^{-2}mol/L.atm[/tex]
[tex]C_{CH_4}[/tex] = molar solubility of methane gas = ?
[tex]p_{CH_4}[/tex] = partial pressure of methane gas = 1.48 atm
Putting values in above equation, we get:
[tex]C_{CH_4}=9.88\times 10^{-2}mol/L.atm\times 1.48atm\\\\C_{CH_4}=0.0146M[/tex]
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]
Given mass of methane = ?
Molar mass of methane = 16.0 g/mol
Molarity of solution = 0.0146 M
Volume of solution = 3.00 L
Putting values in above equation, we get:
[tex]0.0146=\frac{\text{Mass of methane}}{16.0g/mol\times 3.00}\\\\\text{Mass of methane}=(0.0146\times 16\times 3)=0.7008g[/tex]
Hence, the mass of methane that will dissolve is 0.7008 grams