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The pilot of an airplane traveling 45 m s wants to drop supplies to flood victims isolated on a patch of land 160 m below. The supplies should be dropped when the plane is how far from the island?

Answer :

Answer:

257.13 m from the island

Explanation:

Using the equations of motion

uᵧ = vertical component of the initial velocity = 0 m/s

g = 9.8 m/s²

y = 160 m

Time of flight = ?

y = uᵧt + gt²/2

160 = 0 + 4.9t²

t² = 32.65

t = 5.714 s

Note uₓ = horizontal component of the initial velocity = 45 m/s

Range of/horizontal distance covered by the dropped package = uₓ t = 45 × 5.714 = 257.13 m

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