Answered

An 7.50 mL aliquot of a 125 ppm stock Red 40 dye solution was diluted to a final volume of 25.0 mL with deionized water. What is the concentration of the dilute Red 40 dye solution (in ppm)?

Answer :

Answer:

The concentration is equal to 37.5 ppm

Explanation:

This exercise is about dilutions. We have the following data:

V1 = aliquot volume = 7.5 mL

C1= aliquot concentration  = 125 ppm

V2 = final volume = 25 mL

C2 = final concentration of Red 40 dye = unknown

the formula is as follows:

V1xC1 = V2xC2

Clearing C2:

C2 = V1xC1/V2 = (7.5 mL x 125 ppm)/25 mL = 37.5 ppm

Cricetus

The red 40 dye's concentration will be "37.5 ppm".

Volume and concentration:

A solution's concentration seems to be a measurement of how much solute has already been decomposed together in a specified solvent as well as a chemical mixture. This same concentrated solution contains significant amounts of the absorbed component.

According to the question,

Aliquot volume, V₁ = 7.5 mL

Final volume, V₂ = 25 mL

Aliquot concentration, C₁ = 125 ppm

Let,

Final concentration be "C₂".

As we know the relation,

→ V₁ × C₁ = V₂ × C₂

then,

Final concentration will be:

C₂ = [tex]\frac{V_1\times C_1}{V_2}[/tex]

By substituting the values, we get

    = [tex]\frac{7.5\times 125}{25}[/tex]

    = [tex]37.5[/tex] ppm

Thus the above response is correct.

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