Answer :
Answer:
The speed of space station floor is 49.49 m/s.
Explanation:
Given that,
Mass of astronaut = 56 kg
Radius = 250 m
We need to calculate the speed of space station floor
Using centripetal force and newton's second law
[tex]F=mg[/tex]
[tex]\dfrac{mv^2}{r}=mg[/tex]
[tex]\dfrac{v^2}{r}=g[/tex]
[tex]v=\sqrt{rg}[/tex]
Where, v = speed of space station floor
r = radius
g = acceleration due to gravity
Put the value into the formula
[tex]v=\sqrt{250\times9.8}[/tex]
[tex]v=49.49\ m/s[/tex]
Hence, The speed of space station floor is 49.49 m/s.