Answer :
Answer:
The equation to find the width of Erins bedroom is [tex]12\times w =60[/tex].
Width of Erins Bedroom is 5 feet.
Step-by-step explanation:
Given:
Length of the bedroom [tex](l)[/tex] = [tex]12\ ft^2[/tex]
Area of the bedroom = [tex]60 \ ft^2[/tex]
We need to find the width of the bedroom [tex](w)[/tex].
Solution:
Now we know that;
Area of the rectangular bedroom is equal to length of the bedroom times width of the bedroom;
framing in equation form we get;
[tex]Area= l\times w[/tex]
[tex]12\times w =60[/tex]
Hence The equation to find the width of Erins bedroom is [tex]12\times w =60[/tex].
On Solving the equation we get;
Dividing both side by 12 we get;
[tex]\frac{12\times w}{12}=\frac{60}{12}\\\\w= 5\ ft[/tex]
Hence Width of Erins Bedroom is 5 feet.