Answer :
Answer:
The current in the wire = 39.53 A.
Explanation:
The given cross -sectional area of the wire = 1.35 [tex]mm^2[/tex].
The number of electrons flowing in the wire at any point is
= 5.41 [tex]\times 10^{20}[/tex] electrons.
The charge of an electron is known to be = [tex]1.6 \times 10^{-19} \hspace{0.1cm} Coulombs[/tex]
The electronics flow across the wire for a time of, t = 2.19 seconds.
The current in the wire = (number of electrons) × [tex]\frac{charge \hspace{0.1cm} of \hspace{0.1cm} an \hspace{0.1cm} electron}{time}[/tex]
= 5.41 [tex]\times 10^{20}[/tex] × [tex]\frac{1.6 \times 10^{-19}}{2.19}[/tex]
= 39.53 A.
The formula for current is actually, i = [tex]\frac{dq}{dt}[/tex] .
The (number of electrons )×(charge of an electron) will equal the total charge flowing through the wire in the given time = 2.19 seconds.
The current in the wire = 39.53 A.