Answer :
Answer:
36.50$
Step-by-step explanation:
The power of the light bulb in this problem is
P = 100 W = 0.1 kW
And the light bulb is operated for a time of
t = 10 hours
per day.
The light bulb is operated over 1 year (365 days), so the number of hours of operation is:
[tex]T=t\cdot 365 = 10 \cdot 365 =3650 h[/tex]
So the total energy consumed by the light bulb is
[tex]E=PT=(0.1 kW)(3650 h)=365 kWh[/tex]
We know that the cost of operation is
p = 10 cents/kWh
Therefore, the total cost will be:
[tex]c=E\cdot p =(365)(10)=3650 c[/tex]
So, 3650 cents, or 36.50$.