An x-ray beam of wavelength 1.4×10−10m makes an angle of 20° with a set of planes in a crystal(the Bragg angle)causing first order constructive interference.10)(5pts) At what Bragg angle will the second order line appear?

Answer :

Answer:

Second order line appears at 43.33° Bragg angle.

Explanation:

When there is a scattering of x- rays from the crystal lattice and interference occurs, this is known as Bragg's law.

The Bragg's diffraction equation is :

[tex]n\lambda=2d\sin\theta[/tex]      .....(1)

Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.

Given :

Wavelength, λ = 1.4 x 10⁻¹⁰ m

Bragg's angle, θ = 20°

Order of constructive interference, n =1

Substitute these value in equation (1).

[tex]1\times1.4\times10^{-10} =2d\sin20[/tex]

d = 2.04 x 10⁻¹⁰ m

For second order constructive interference, let the Bragg's angle be θ₁.

Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).

[tex]2\times1.4\times10^{-10} =2\times2.04\times10^{-10} \sin\theta_{1}[/tex]

[tex]\sin\theta_{1} =0.68[/tex]

θ₁ = 43.33°

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