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A car rounds an unbanked curve of radius 65 m. If the coefficient of static friction between the road and car is 0.70, what is the maximum speed at which the car can traverse the curve without slipping?

Answer :

Answer:

v = 21.127 m/s

Explanation:

Let's start off with the equation for centrifugal force:

[tex]F = m*v^2 / r[/tex]

This force has to be equal to the force of friction which is:

[tex]F=u * R[/tex]   (where u = coefficient of friction and R = mass * gravity )

Assumption: The car is travelling on horizontal ground

We can set the above equations equal to one another to get:

(m*v^2)/r = u * (m * 9.81)

here u = 0.7

r = 65

and mass cancels out on each side

Solving for v, we get:

v = 21.127 m/s

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