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A child sitting 1.90 m from the center of a merry-go-round moves with a speed of 2.05 m/s . Calculate the centripetal acceleration of the child. Calculate the net horizontal force exerted on the child. (mass = 28.5 kg ).

Answer :

Onoriodefelix

Answer:

Acceleration = 2.21m/s^2

Force = 62.99N

Explanation:

Centripetal acceleration = v^2 / r

Given velocity v = 2.05m/s

Radius r = 1.90m

Centripetal acceleration = (2.05)^2 /1.90

2.05 x 2.05 /1.90

4.2025/1.90

2.21m/s^2

Now , since a = 2.21 m/s^2

And mass m = 28.5kg

Force exerted on the child = mass x centripetal acceleration

That’s 28.5kg x 2.21m/s^2

62.99N

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