Answer :

sqdancefan

Answer:

  see below

Step-by-step explanation:

You can always multiply these out to find what works.

First of all, you can look at the product of the constants. In order for the product to be -35, they must have different signs. That excludes choices A and B.

In order for the x-term of the product to be -2, the binomial constants must have a sum of -2. That excludes choice D.

The only viable choice is C.

${teks-lihat-gambar} sqdancefan

(x+5)(x-7)

Step-by-step explanation:

The given equation is

x^2-2x-35

Here we need to split 35 in a way that the multiplication of the numbers should yield 35 while the addition needs to be equal to the middle term of the equation that is -2x

So if i consider the factors of 35, i can take 7 and 5

first condition is multiplication should be 35, so

                           7*5 = 35

second condition says addition needs to be equal to the middle term of the equation

                         -7x+5x = -2x

so both the conditions are satisfying so we can break the equation now

             x^2-7x+5x-35

taking the common terms out

          x(x-7)+5(x-7)

          (x+5)(x-7)

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