Option A:
[tex]$ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}[/tex]
Solution:
Given data:
AB = 50, BC = 48, AC = 14
To find the value of sin A and cos A:
[tex]$\sin A= \frac{Opposite \ side}{Hypotenuse}[/tex]
[tex]$\sin A= \frac{AC}{AB}[/tex]
[tex]$\sin A= \frac{14}{50}[/tex]
[tex]$\cos A= \frac{Adjacent \ side}{Hypotenuse}[/tex]
[tex]$\cos A= \frac{BC}{AB}[/tex]
[tex]$\cos A= \frac{48}{50}[/tex]
[tex]$\therefore \ \sin A= \frac{14}{50}, \ \cos A= \frac{48}{50}[/tex]
Hence option A is the correct answer.