Answer :
Answer:
[tex]W=3.024[J][/tex]
Explanation:
The work done by the stretching forces is given by this equation:
[tex]W=\frac{1}{2}\frac{E*A*\Delta L^{2} }{L_{0}}[/tex] (1)
Where:
- W is the work done
- E is the Young's modulus (E = 21000 N/cm²)
- A is the cross-sectional area ([tex]A=\pi (D/2)^{2}[\tex]=0.20 cm^{2})
- ΔL is the amount by which the length of the object changes (ΔL=12 cm)
- L(0) is the initial length (L(0) = 10 m = 1000 cm)
We just need to put it in the equation (1):
[tex]W=\frac{1}{2}\frac{21000*0.20*12^{2}}{1000}=302.4 [N*cm][/tex]
Therefore the work done is:
[tex]W=3.024[J][/tex]
I hope it helps you!