Answer :
Explanation:
As the small pulley and mass are not moving, they are stationary.
[tex]T_{2} = T_{1}[/tex] = mg = (2.27)(9.8)
= 22.246 N
Now resolve the force in the opposite direction.
F = 2Tcos30°
F = (2)(22.246)(cos30°)
F = 38.53 N
Explanation:
As the small pulley and mass are not moving, they are stationary.
[tex]T_{2} = T_{1}[/tex] = mg = (2.27)(9.8)
= 22.246 N
Now resolve the force in the opposite direction.
F = 2Tcos30°
F = (2)(22.246)(cos30°)
F = 38.53 N