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A hiker walks 2.00 km north and then 3.00 km east, all in 2.50 hours. Calculate the magnitude and direction of the hiker’s (a) displacement (in km) and (b) average velocity (in km/h) during those 2.50 hours. (c) What was her average

Answer :

Kazeemsodikisola

Answer:

Incomplete third question

I think it should be

C. What was her average speed

Explanation:

Check attachment for solution

${teks-lihat-gambar} Kazeemsodikisola
${teks-lihat-gambar} Kazeemsodikisola

(a). The displacement is 3.6km.

(b). Average velocity is 2 km/hour

(a). A diagram is attached below which describe situation of   question.

In diagram OB represent the displacement.

In right triangle OAB,

          [tex](OB)^{2}=(OA)^{2}+(AB)^{2}\\ \\ OB^{2}=2^{2}+3^{2}=4+9=13\\ \\ OB=\sqrt{13}=3.6Km[/tex]

(b). Average velocity is given as,

                  [tex]v=\frac{Distance}{time}=\frac{2+3}{2.5} =5/2.5=2km/h[/tex]

Learn more about Displacement and Average velocity here:

https://brainly.com/question/862972

${teks-lihat-gambar} ibiscollingwood

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