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A baseball (m = 145 g) traveling 32 m/s moves a fielder's glove backward 25 cm when the ball is caught. What was the average force exerted by the ball on the glove?

Answer :

MathPhys

Answer:

297 N

Explanation:

First, find the acceleration of the ball.

Given:

Δx = 0.25 m

v₀ = 32 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (32 m/s)² + 2a (0.25 m)

a = -2048 m/s²

Find the force exerted on the ball by the glove.

F = ma

F = (0.145 kg) (-2048 m/s²)

F = -297 N

The force exerted by the ball on the glove is equal and opposite.

-F = 297 N

Round as needed.

onyebuchinnaji

The average force exerted by the ball on the glove when it was caught is 297 N.

The given parameters:

  • mass of the baseball, m = 145 g = 0.145 kg
  • speed of the baseball, u = 32 m/s
  • distance moved, d = 25 cm = 0.25 m

The acceleration of the baseball is calculated as follows

[tex]v^2 = u^2 + 2as\\\\0 = 32^2 + 2(-0.25)a\\\\0 = 1024 - 0.5a\\\\0.5a = 1024\\\\a = 2048 \ m/s^2[/tex]

The average force exerted by the ball on the glove when it was caught is calculated as follows:

[tex]F = ma\\\\F = 0.145 \times 2048\\\\F = 297 \ N[/tex]

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