Answer :
Answer:
In 1 seconds after being thrown will the stone reach its maximum height.
Step-by-step explanation:
Given : Ming throws a stone off a bridge into a river below. The stone's height (in meters above the water), 3 seconds after Ming threw it, is modeled by : [tex]h(x) = -5(x - 1)^2 + 45[/tex].
To find : How many seconds after being thrown will the stone reach its maximum height?
Solution :
The maximum height is attain by getting the vertex of the model.
The vertex form of the quadratic equation or parabola is
[tex]f (x) = a(x - h)^2+ k[/tex]
Where, (h,k) are the vertex.
On comparing with the given model, [tex]h(x) = -5(x - 1)^2 + 45[/tex]
a=-5, h=1 and k=45
The vertex of the equation is (h,k)=(1,45).
Now the maximum height is 45 m and number of second is 1 sec.
Therefore, In 1 seconds after being thrown will the stone reach its maximum height.