Answer :

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Answer:

10[tex]\leq[/tex]D+R

D[tex]\geq[/tex]R/3 (or 3D[tex]\geq[/tex]R)

Step-by-step explanation:

Say that D = Decaf and R = Regular

10[tex]\leq[/tex]D+R

D[tex]\geq[/tex]R/3 (or 3D[tex]\geq[/tex]R)

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