Answer :
Check the picture below.
[tex]\bf \textit{volume of a sphere}\\\\ V = \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r = 5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3} \\\\\\ V=\cfrac{500\pi }{3}\implies V\approx 523.6[/tex]
