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A constant force of magnitude 4.9 N makes an angle of 130o (measured counterclockwise) with the positive x direction as it acts on a 2.0 kg object moving in the xy plane. How much work is done on the object by the force as the object moves from the origin to the point having position vector?

Answer :

The work done is 3 S

Explanation:

A constant force of 4.9 N is applied on the body in the horizontal and positive direction .

The object moves in x-y plane making an angle of 130° with horizontal .

Thus the work done can be calculated by the dot product of force and displacement S ( say )

Thus the work done = F . S = F S cos 130

= - 4.9 x 0.6 x S =  - 3 S approx

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