Answer :
Answer:
Step-by-step explanation:
Given that every day at noon, a bus leaves for Townville and travels at a speed of x kilometers per hour. Today, the bus left 30 minutes late.
If the driver drives 7/6 times as fast as usual, she will arrive in Townville at the regular time.
If correct time leaves then distance = time *speed
280 = t*x where t is the time in hours
Or t = 280/x
Now speed changes to 7x/6 while time changes to (t-1/2)
So 280 = (t-1/2) 7x/6
[tex]280 = (\frac{280}{x} -\frac{1}{2} )(\frac{7x}{6} )\\240= (\frac{280}{x} -\frac{1}{2} )x\\\\x=80[/tex]
x = 80 km per hour