Answer :
Answer:
3.417 X [tex]10^{-9}[/tex]
Explanation:
Dealing seven cards indicates that they are not being replaced. The chance o getting two triples and one other card is as follows:
P(king of hearts) = 4/52 = 1/13 This is because there are 4 kings in a deck of cards.
P(king of spades) = 3/51 = 1/17 This is because there are three kings left in the deck and 51 cards left in the deck
P(king of spades) = 2/50 = 1/25 reduced number of kings and cards
P(Ten of diamonds) = 4/49 There are four tens in the deck but there are only 49 cards there.
P(ten of spades) = 3/48 = 1/16 Reduced number of tens and cards
P(ten of clubs) = 2/47
P(Three of hearts) = 4/46 There are four threes in a now reduced deck.
P(three of a kind and one other card): (1/13)(1/17)(1/25)(4/49)(1/16)(2/47)(4/46)
numerators = 1 X 1 X 1 X 4 X 1 X 2 X 4 = 32
denominators = 13 X 17 X 25 X 49 X 16 X 47 X 46 = 9364919200
numerators/denominators = 32/9364919200 = 3.417 X [tex]10^{-9}[/tex]
Answer:
0.02
Explanation:
Let the heart, h = 3 ⇒ 3/52 = 1/14
Spade, s = 10 ⇒ 10/52 = 5/26
Club, c = 10⇒ 5/26
Diamond, d = 10⇒ 5/26
Using, nCr * (h)∧r * (s)∧n-r * (c)∧n-r * (d)∧n-r
7C1 * (1/14)*(5/26)²*(5/26)²*(5/26)² = 0.02