Answer :
Answer:
Step-by-step explanation:[tex]V(t)= 42(1-e ^{1.5t} ) +36[/tex] is given value in dollars of a stock in t months after it is purchased.
a) Substitute 1 for t
[tex]V(1) = 42(1-e^{-1.5} )+36 \\=67.852\\=67.85[/tex]
V(12) = [tex]V(1) = 42(1-e^{-1.5*12} )+36 \\=77.00[/tex]
b) Find derivative for V
[tex]V'(t) = 42(-1.5) e^{-1.5t} )\\\\=-63e^{-1.5t}[/tex]
c) When V(t) = 75
[tex]V(t)=75= 42(1-e ^{1.5t} ) +36\\1-e ^{1.5t=0.9286\\=-2.639[/tex]
d) As t tends to infinity, exponent being in negative t tends to 0
So V tends to 42(1-0)+36 = 78