Answer :
Explanation:
Given that,
Frequency of the power line, f = 6 Hz
Value of maximum electric field strength of 11.6 kV/m
(a) The wavelength of this very low frequency electromagnetic wave is given by using relation as :
[tex]c=f\lambda[/tex]
[tex]\lambda=\dfrac{c}{f}[/tex]
[tex]\lambda=\dfrac{3\times 10^8\ m/s}{60\ Hz}[/tex]
[tex]\lambda=5\times 10^6\ m[/tex]
(b) As its can be seen that the wavelength of this wave is very high. It shows that it is a radio wave.
(c) The relation between the maximum magnetic field strength and maximum electric field strength is given by :
[tex]B_0=\dfrac{E_0}{c}\\\\B_0=\dfrac{11.6\times 10^3}{3\times 10^8}\\\\B_0=3.86\times 10^{-5}\ T[/tex]
So, the maximum magnetic field strength is [tex]3.86\times 10^{-5}\ T[/tex].
Answer:
a) [tex]\lambda=5\times 10^6\ m[/tex]
b) The wavelength of the obtained is greater than 1mm so it lies in the range of radio waves.
c) [tex]B_m=3.867\times 10^{-5}\ T[/tex]
Explanation:
Given:
frequency of electromagnetic waves, [tex]f=60\ Hz[/tex]
maximum field strength of the electric field, [tex]E_m=11600\ V.m^{-1}[/tex]
Since the velocity of electromagnetic waves is, [tex]c=3\times 10^8\ m.s^{-1}[/tex]
a)
We know the relation between the frequency and wavelength is given as:
[tex]\lambda=\frac{c}{f}[/tex]
[tex]\lambda=\frac{3\times 10^{8}}{60}[/tex]
[tex]\lambda=5\times 10^6\ m[/tex]
b)
The wavelength of the obtained is greater than 1mm so it lies in the range of radio waves.
c)
The maximum magnetic field can be calculated as:
[tex]B_m=\frac{E_m}{c}[/tex]
[tex]B_m=\frac{11600}{3\times 10^8}[/tex]
[tex]B_m=3.867\times 10^{-5}\ T[/tex]