Answered

A clothing store has a rectangular clearance section with a length that is twice the width w. During a sale, the section is expanded to an area of (2w^2 + 11w + 12) ft^2. Find the amount of the increase in the length and width of the clearance section.

Answer :

calculista

Answer:

see the explanation

Step-by-step explanation:

step 1

The original area of the rectangular clearance section is equal to

[tex]A=LW[/tex] ----> equation A

we know that

The length is twice the width

[tex]L=2W[/tex] ----> equation B

substitute equation B in equation A

[tex]A=(2W)W[/tex]

[tex]A=2W^2\ ft^2[/tex]

step 2

During a sale, the section is expanded to an area of

[tex]A=(2W^2+11W+12)\ ft^2[/tex]

so

To find out the amount of the increase in the length and width of the clearance section, subtract the areas

[tex](2W^2+11W+12)\ ft^2-2W^2\ ft^2=(11W+12)\ ft^2[/tex]

therefore

The amount of the increased area is [tex](11W+12)\ ft^2[/tex]

Other Questions