Answer :
Answer:
Electric field due to uniformly charged sphere is 9.2 x 10⁴ N/C
Explanation:
Given :
Radius of the solid sphere, R = 42 cm = 0.42 m
Total charge on the sphere, Q = 23 μC = 23 x 10⁻⁶ C
Distance of the point from the center of the sphere, r = 150 cm = 1.5 m
Since, r > R, so the point is outside the sphere. Thus, the electric field outside the uniformly charged sphere is determine by the relation:
[tex]E=\frac{kQ}{r^{2} }[/tex]
Here k is constant and its value is 9 x 10⁹ N·m²/C².
Substitute the suitable values in the above equation.
[tex]E=\frac{9\times10^{9}\times23\times10^{-6} }{(1.5)^{2} }[/tex]
E = 9.2 x 10⁴ N/C