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"A student takes 152 mL of a 3.0M HCl solution and places it into a beaker. The student then adds enough water to the beaker to make 750 mL. Calculate the molarity of this new solution."

Answer :

Answer: I think it's 0.608

Explanation: (152×3.0)÷750=0.608

Also the number of moles of the first solution is .456, so if we apply that to the new solution we get .456÷.750=.608

Sorry if wrong

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