Answered

Hydroxylamine nitrate contains 29.17 mass % N, 4.20 mass % H, and 66.63 mass O. If its molar mass is between 94 and 98 g/mol, what is its molecular formula

Answer :

bhuvna789456

The molecular formula is N2H4O4.

Explanation:

Assume 100 g of this compound  

mass N = 29.17 g

mass H = 4.20 g

mass O = 66.63 g  

moles N = 29.17 g/ 14.0067 g/mol = 2.083

moles H = 4.20 g/ 1.008 g/mol = 4.16

moles O = 66.63 g/ 15.999 g/mol = 4.16

The smallest number is divided to get the ratio as N:H:O

                [tex]\frac{4.16} {2.083} = 2[/tex] -----> H and O

                 [tex]\frac{2.083}{2.083} = 1[/tex] -----> N  

the empirical formula is calculated as NH2O2 ( molar mass = 48.03 g/mol)

96.04 / 48.03 = 2

By  multiplying the empirical formula by 2, we get

The molecular formula is N2H4O4.

The molecular formula will be :

Assume :

100 g of this compound  

Mass

  • mass N = 29.17 g
  • mass H = 4.20 g
  • mass O = 66.63 g  

Moles

  • moles N = 29.17 g/ 14.0067 g/mol = 2.083
  • moles H = 4.20 g/ 1.008 g/mol = 4.16
  • moles O = 66.63 g/ 15.999 g/mol = 4.16

The smallest number is divided to get the ratio as N:H:O

    4.16/2.083=2  -----> H and O

     2.083/2.083   -----> N  

The empirical formula is calculated as NH2O2 ( molar mass = 48.03 g/mol)

96.04 / 48.03 = 2

Thus, the molecular formula is N2H4O4.

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