Answer :
Answer:
7.14x10⁻⁴ M
Explanation:
To calculate the concentration of the enzyme we need to use the Michaelis–Menten equation:
[tex] v = \frac{V_{max}*[S]}{K_{m} + [S]} [/tex]
Where:
v: is the reaction rate of the reaction
Vmax: is the maximum rate achieved by the system
[S]: is the concentration of the substrate
Km: is the Michaelis constant
Having that:
v = Vmax/8 and Km = 0.0050 M
The concentration of the enzyme is:
[tex] v = \frac{V_{max}*[S]}{K_{m} + [S]} [/tex]
[tex] \frac{V_{max}}{8} = \frac{V_{max}*[S]}{0.0050 M + [S]} [/tex]
[tex] 0.0050 M + [S] - 8[S] = 0 [/tex]
[tex] [S] = \frac{0.0050 M}{7} = 7.14 \cdot 10^{-4} M [/tex]
Therefore, the concentration of the enzyme is 7.14x10⁻⁴ M.
I hope it helps you!