Answer :

[tex]i^2(2i^2-5) \rightarrow 7[/tex]
[tex]i^2(3+i^2) \rightarrow -2[/tex]
[tex]2i(2i-i^3) \rightarrow -6[/tex]
[tex]i(4i^3-i) \rightarrow 5[/tex]

Answer:

Distributive property says that:

[tex]a \cdot (b+c) =a\cdot b+ a\cdot c[/tex]

We know that

[tex]i^2= -1[/tex] where i is the imaginary

Given the complex numbers:

A.

[tex]i^2(2i^2-5)[/tex]

⇒[tex]-1(2(-1)-5) = -1(-2-5)= -1(-7) = 7[/tex]

B.

[tex]i^2(3+i^2)[/tex]

⇒[tex]-1(3+(-1)) = -1(3-1)= -1(2) = -2[/tex]

C.

[tex]2i(2i-i^3)[/tex]

Using distributive property

⇒[tex]4i^2-2i^4[/tex]

⇒[tex]4(-1)-2(i^2)^2 = -4-2(-1)^2 = -4 -2 = -6[/tex]

D.

[tex]i(4i^3-i)[/tex]

Using distributive property

⇒[tex]4i^4-i^2[/tex]

⇒[tex]4(i^2)^2-i^2[/tex]

⇒[tex]4(-1)^2-(-1) = 4+1 = 5[/tex]

Therefore. matching defined as:

A. [tex]i^2(2i^2-5)[/tex]  → 7

B. [tex]i^2(3+i^2)[/tex]  → -2

C. [tex]2i(2i-i^3)[/tex]  → -6

D. [tex]i(4i^3-i)[/tex]    →  5

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