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Mr. Shaw graphs the function f(x) = –5x + 2 for his class. The line contains the point (-2, 12). What is the point-slope form of the equation of the line he graphed?

Answer :

olemakpadu
f(x) = -5x + 2,   let f(x) = y

y = -5x + 2.   Comparing to y = mx + c, the slope m = -5,

The point (-2, 12) is the (x₁, y₁)

The point slope form is :

y - y₁ = m(x - x₁),    slope m = -5

y - 12 = -5(x - -2)

y - 12 = -5(x + 12)

f(x) - 12 = -5(x + 12)  is the point - slope form.
mvelazcoa

Answer:

y-12=-5(x+2)

Step-by-step explanation:

the point slope equation formula is

y-y₁=m(x-x₁)

being (x₁;y₁) = (-2, 12) and m= -5

then

y-12=-5(x+2)

to check that is the same equation we can isolate y

y=-5(x+2)+12

y=-5x-10+12

y=-5x+2

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