Answer :
Answer:
The energy is dissipated in the resistor at the rate of 0.482 W
Explanation:
Given :
Potential difference resistor [tex]V_{1} =[/tex] 12 V
Energy dissipated in the resistor [tex]P_{1} =[/tex] 0.630 W
New potential difference [tex]V_{2} =[/tex] 10.5 V
We know that energy dissipated per unit time through resistor is given by,
⇒ [tex]P = VI = \frac{V^{2} }{R}[/tex]
Rate of energy dissipated is proportional to the square of the applied potential.
So for new potential we can write,
[tex]\frac{P_{2} }{P_{1} } = \frac{V_{2}^{2} }{V_{1} ^{2} }[/tex]
[tex]P_{2} = \frac{0.63 \times 110.25}{144}[/tex]
[tex]P_{2} = 0.482[/tex] W
So new rate of energy dissipation is 0.482 W