Answer :
Answer : The value equilibrium constant for the reaction is, 0.207
Explanation :
The given chemical reaction:
[tex]CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)[/tex]
The expression of [tex]K_p[/tex] for above reaction follows:
[tex]K_p=\frac{P_{COCl_2}}{P_{CO}\times P_{Cl_2}}[/tex]
We are given:
[tex]P_{COCl_2}=0.170atm[/tex]
[tex]P_{CO}=0.720atm[/tex]
[tex]P_{Cl_2}=1.14atm[/tex]
Putting values in above equation, we get:
[tex]K_p=\frac{0.170}{0.720\times 1.14}\\\\K_p=0.207[/tex]
Thus, the value equilibrium constant for the reaction is, 0.207