Answered

for the reaction 2Fe + O2 = 2FeO, how many grams of iron oxide are produced from 8.00 mol of iron? when o2 is an excess

Answer :

akindeleot

Answer:

2Fe + O₂ -------------------> 2FeO

8 mol Fe produce

8 mol Fe * 2 mol FeO / 2 mol Fe = 8 mol FeO

Mass of FeO = 8 mol FeO * 71.85 g/mol = 574.8 grams FeO

Explanation:

Having 8 mol of Iron means 8 moles of iron oxide can be produced. Each mole of iron oxide has a molecular weight of 71.85 grams. Therefore, 8 moles of iron oxide should weight 574.8 grams.

The number of grams of iron is 574.8.

The calculation of the number of moles:

Since

2Fe + O₂ -------------------> 2FeO

Here

8 mol Fe produced

So,

= 8 mol Fe * 2 mol FeO / 2 mol Fe

= 8 mol FeO

Now

Mass of FeO is

= 8 mol FeO * 71.85 g/mol

= 574.8 grams FeO

Here. Each mole of iron oxide has a molecular weight of 71.85 grams.

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