Answer:
A': (3,9)
B': (4,0)
C': (5,5)
Step-by-step explanation:
A': (5-2,6+3) = (3,9)
B': (6-2,-3+3) = (4,0)
C': (7-2,2+3) = (5,5)
The equivalent vertices of the triangle A'B'C' will be (3, 9), B'(4, 0), and C'(5, 5)
Given the vertices of a triangle ABC with the vertices A(5,6) B(6,-3), and C(7,2).
If the coordinate is translated 2 units to the left and 3 units up, the resulting coordinates of the triangle will be expressed as;
A' = (5 - 2, 6 + 3) = (3, 9)
B' = (6 - 2, -3 + 3) = (4, 0)
C' = (7 - 2, 2 + 3) = (5, 5)
Hence the equivalent vertices of the triangle A'B'C' will be (3, 9), B'(4, 0), and C'(5, 5)
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