Answer :
Answer:
a) [tex]V=49.5MV[/tex]
b)[tex]r=49.5m[/tex]
c) [tex]\Delta U=3*(49.5-1)=145.5 MeV[/tex]
Explanation:
a) The potential equation is given by:
[tex]V=k\frac{Q}{r}[/tex]
k is the electrostatic constant ([tex]k=9.9*10^{9}Nm^{2}/C^{2}[/tex])
Q is the charge Q = 5mC
r is the radius of the sphere r = 1 m
[tex]V=9.9*10^{9}\frac{5*10^{-3}}{1}=49.5MV[/tex]
b) We solve it using the same equation.
Here we need to find r:
[tex]r=k\frac{Q}{V}[/tex]
[tex]r=9.9*10^{9}\frac{5*10^{-3}}{1*10^{6}}[/tex]
[tex]r=49.5m[/tex]
c) The relation between difference potential and electrical energy is:
[tex]\Delta U=\Delta Vq[/tex]
here q is 3e becuase oxygen atom has three missing electrons
Therefore:
[tex]\Delta U=3*(49.5-1)=145.5 MeV[/tex]
I hope it heps you!