Answer :
Answer: The final pressure of the gas is 80.0kPa
Explanation:
From Boyle's gas law, which states that "the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature"
Mathematically, P ∝ (1/V)
This means that,
the pressure of a gas tends to increase as the volume of the container decreases, and also the pressure of a gas tends to decrease as the volume of the container increases.
Since P ∝ (1/V), we can then write that
P = k(1/V)
Where P is the pressure, V is the volume and k is the proportionality constant
Therefore,
PV = k
We can then write that
P1V1 = P2V2 = P3V3 = ...
Hence, P1V1 = P2V2
Where P1 is the initial pressure of the gas
P2 is the final pressure of the gas
V1 is the initial volume of the gas
and V2 is the final volume of the gas
From the question,
V1 = 10.0L
P1 = 232.0 kPa
V2 = 29.0L
P2 = ??
From P1V1 = P2V2
232.0kPa × 10.0L = P2 × 29.0L
Hence,
P2 = (232.0kPa × 10.0L) / 29.0L
P2 = 80.0kPa
Hence, the final pressure of the gas is 80.0kPa
Answer:
80 kPa or 8.0×10⁴ Pa.
Explanation:
From Boyle's law,
PV = P'V'........................ Equation 1
Where P = Initial pressure, V = Initial volume, P' = Final pressure, V' = Final volume.
Make P' the subject of the equation
P' = PV/V'.................... Equation 2
Given: P = 232 kPa, V = 10.0 L, V' = 29.0 L
Substitute into equation 2
P' = 232(10)/29
P' = 80 kPa or 8.0×10⁴ Pa.
Hence the final pressure of the gas = 80 kPa or 8.0×10⁴ Pa.