Answer :
Answer:
The over all work done is 141.4kJ
Explanation:
Given that,
p1 = 0.5 MPa
T1 = 267°C
Calculate the gas costant of cardondioxide
[tex]R = \frac{8.314}{ Molar .mass} \\\\[/tex]
[tex]R= \frac{8.314}{44} \\\\= 0.1889kJ/kg.k[/tex]
Calculate the work done during the process 1-2
[tex]W_1-_2 = p_1v_1 In\frac{v_2}{v_1}[/tex]
[tex]= mRTIn\frac{v_2}{v_1}[/tex]
[tex]2 \times 0.1889 \times (267 + 273)In\frac{2v_1}{v_1} \\\\= 141.4kJ[/tex]
Considering that the process 2-3 is constant volume process,
hence the work done is zero
[tex]W_2 - _3 = 0[/tex]
Calculate the over all work done
[tex]W = W_1-_2 + W_2-_3\\ W = 141.4kJ + 0\\W = 141.4kJ[/tex]
The over all work done is 141.4kJ