Answer :
Answer:
Required answer is 97.72%.
Step-by-step explanation:
Given mean [tex]\mu =50[/tex] and standard deviation [tex]\sigma =10[/tex]. We need to find [tex]P\left ( X>30 \right )[/tex]. using z score
[tex]z=\frac{X-\mu }{\sigma }=\frac{30-50}{10}=\frac{-20}{10}=-2[/tex]
So,
[tex]P\left ( X>30 \right )=P\left ( X>-2 \right )=P ( Z<2 )=0.9772=97.72\%[/tex]
Required answer is 97.72%.