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The rigid bar is supported by the two short white spruce wooden posts and a spring. If each of the posts has an unloaded length of 1 m and a cross-sectional area of 600 mm2, and the spring has a stiffness of k = 2 MN >m and an unstretched length of 1.02 m, determine the force in each post after the load is applied to the bar.

Answer :

braza909

Answer:

Force in each post=Fa=Fb=25.6KN

Explanation:

Using equations of equilibrium=∑Fx=0

Fb-Fa=0

Fb=Fa=F

∑Fy=0

2F+Fsp-100(10^3)=0              (1)

Now using compatibility relationships

δa+0.02=δsf

0.1727F+20(10^3)=0.5Fsp   (2)

Solve equation(1) and equation(2)

Force in post=25.6 KN

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