Answer :
Answer:
[tex]3\frac{3}{8} \ inches[/tex]
Step-by-step explanation:
Given:
Alison is making a 16 inch necklace.
The first 4 1/4 inches filled with red beads.
And 8 3/8 inches are filled with blue beads.
The rest has white beads.
Question asked:
How many inches are filled with white beads ?
Solution:
Total length of necklace in inches = 16
Length of necklace filled with red beads in inches = [tex]4\frac{1}{4}=\frac{4\times4+1}{4} =\frac{17}{4}[/tex]
Length of necklace filled with blue beads in inches = [tex]8\frac{3}{8}=\frac{8\times8+3}{8} =\frac{67}{8}[/tex]
Length of necklace filled with white beads in inches = Total length of necklace - (Length of necklace filled with red beads + Length of necklace filled with blue beads)
Length of necklace filled with white beads in inches [tex]=16-(\frac{17}{4} +\frac{67}{8} )\\[/tex]
[tex]=16-(\frac{17\times2+67\times1}{8} )\\\\ =16-(\frac{34+67}{8}) \\\\ =16-\frac{101}{8} \\\\ =\frac{16\times8-101\times1}{8} \\\\ =\frac{128-101}{8} \\ \\ =\frac{27}{8} \\ \\ =3\frac{3}{8}[/tex]
Thus, [tex]3\frac{3}{8} \ inches[/tex] are filled with white beads in necklace.