Answer :
The answer is 50.8 miles per hour.
The formula is [tex]s=2 \sqrt{5l} [/tex]
If l = 129 feet, we will implement it in the formula:
[tex]s=2 \sqrt{5l} =2 \sqrt{5*129} =2 \sqrt{645}= 2*25.4=50.8[/tex]
Thus, the speed of the car that left skid marks 129 feet long was 50.8 miles per hour.
The formula is [tex]s=2 \sqrt{5l} [/tex]
If l = 129 feet, we will implement it in the formula:
[tex]s=2 \sqrt{5l} =2 \sqrt{5*129} =2 \sqrt{645}= 2*25.4=50.8[/tex]
Thus, the speed of the car that left skid marks 129 feet long was 50.8 miles per hour.