A charge of 4.5 x 10^-5 C is placed in an electric field with a strength of 2.0 x 10^4 N/C. If the charge is 0.030 m from the source of the electric field, what is the electric potential energy of the charge?

Answer :

Answer:

The solved potential energy comes out is 0.027 Joules.

Explanation:

The formula for the electrical potential energy (U) is given by

[tex]U = q \times E \times d[/tex]

So now insert the values from question to find the answer

Charge ; q = [tex]4.5 \times 10^{-5} C[/tex]

Electric Field strength ;E = [tex]2.0 \times 10^{4} N/C[/tex]

Distance ;d = 0.030 m

[tex]U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m[/tex]

Simplifying it

[tex]U = 0.027 J[/tex]

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