Answer :
Answer:
We can use the following R code in order to create the histogram:
> x<-c(0.92, 0.90, 0.90, 0.93, 0.92, 0.86, 0.92, 0.86, 0.80, 0.90)
> hist(x)
And we got the figure attached as the result
And as we can see the shape is not bell shaped so then we can conclude that the distribution is not normal
[tex]\bar X= \frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex]\bar X= 0.891[/tex]
We have 10 observations we can calculate the median with the positions 5 and 6 from the dataset ordered and we got:
[tex]Median = \frac{0.9+0.9}{2}=0.9[/tex]
And as we can see the median is different from the mean so then the distribution for the data is not normal for this case.
Step-by-step explanation:
For this case we have the following data given:
0.92 0.90 0.90 0.93 0.92 0.86 0.92 0.86 0.80 0.90
We can sort the data on increasing way and we got:
0.80 0.86 0.86 0.90 0.90 0.90 0.92 0.92 0.92 0.93
We can use the following R code in order to create the histogram:
> x<-c(0.92, 0.90, 0.90, 0.93, 0.92, 0.86, 0.92, 0.86, 0.80, 0.90)
> hist(x)
And we got the figure attached as the result
And as we can see the shape is not bell shaped so then we can conclude that the distribution is not normal
We can calculate the mean with the following formula:
[tex]\bar X= \frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex]\bar X= 0.891[/tex]
We have 10 observations we can calculate the median with the positions 5 and 6 from the dataset ordered and we got:
[tex]Median = \frac{0.9+0.9}{2}=0.9[/tex]
And as we can see the median is different from the mean so then the distribution for the data is not normal for this case.
