Answer :
Answer:
2.46 mol /min
Explanation:
Let's consider the following redox reaction that takes place in a breathalyzer.
2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O
The molar ratio of C₂H₆O to Cr₂(SO₄)₃ is 3:2. We know that the rate of appearance of Cr₂(SO₄)₃ is 1.64 mol/min. We can find the rate of disappearance of C₂H₆O.
(1.64 mol Cr₂(SO₄)₃ / min) × (3 mol C₂H₆O/2 mol Cr₂(SO₄)₃) =
= 2.46 mol C₂H₆O/min
The rate of disappearance is 2.46 mol /min.
What is Redox reaction?
The type of reaction in which oxidation and reduction takes places simultaneously.
Let's consider the following redox reaction that takes place in a breathalyzer.
2 K₂Cr₂O₇ + 8 H₂SO₄ + 3 C₂H₆O → 2 Cr₂(SO₄)₃ + 2 K₂SO₄ + 11 H₂O
The molar ratio of C₂H₆O to Cr₂(SO₄)₃ is 3:2.
Given: rate of appearance of Cr₂(SO₄)₃ is 1.64 mol/min.
To find: rate of disappearance of C₂H₆O=?
Rate of disappearance of C₂H₆O= (1.64 mol Cr₂(SO₄)₃ / min) × (3 mol C₂H₆O/2 mol Cr₂(SO₄)₃)
Rate of disappearance of C₂H₆O= 2.46 mol C₂H₆O/min
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