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Two leopards are fighting over a piece of meat they caught while hunting. The leopards pull on the meat muscle with a force of 100. N, stretching the 0.10-m-long tendon by 0.0080 m. If the cross-sectional area of the tendon is 1.0 105 m2, what is its stretch modulus?

Answer :

Answer:

Stretch Modulus of the given is

[tex]Modulus = 1.25 \times 10^8 N/m^2[/tex]

Explanation:

By the law of elasticity we know that the ratio of stress and strain is known as modulus of elasticity

So here we have

[tex]Modulus = \frac{stress}{strain}[/tex]

here we have

[tex]stress = \frac{Force}{Area}[/tex]

[tex]stress = \frac{100}{1.0 \times 10^{-5}}[/tex]

[tex]stress = 10^7 m^2[/tex]

now similarly we have

[tex]strain = \frac{\Delta L}{L}[/tex]

[tex]strain = \frac{0.0080}{0.10}[/tex]

[tex]strain = 0.08[/tex]

Now we have

[tex]Modulus = \frac{10^7}{0.08}[/tex]

[tex]Modulus = 1.25 \times 10^8 N/m^2[/tex]

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