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The number of customers coming to a store during regualr work hours has an average of 15 customers/hour and follows a Poisson process. A customer walks in what is the probability that the next customer will not arrice for 5 minutes?

Answer :

Answer:

28.65% probability that the next customer will not arrive for 5 minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given time interval.

Mean of 15 customers an hour:

An hour has 60 minutes, so in the space of 5 minutes, the mean is:

[tex]\mu = \frac{15*5}{60} = 1.25[/tex]

A customer walks in what is the probability that the next customer will not arrive for 5 minutes?

This is P(X = 0).

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{1.25}*(1.25)^{0}}{(0)!} = 0.2865[/tex]

28.65% probability that the next customer will not arrive for 5 minutes

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