Answer :

jaealyse211
y-4= -3(x-3)
First you'll distribute the -3(x-3) and you should get -3x+9 (a negative divided by a negative is a positive)
 So your new equation will be y-4=-3x+9. Next you'll get rid of the -4 y adding 4 on both sides of the equation. So you should get y=-3x+13. So points you could use is (0,13),(1,10),(2,7)
dalendrk
[tex]y-y_1=a(x-x_1)\\\\y-4=-3(x-3)\\\\therefore,\ the\ point\ is\ (4;\ 3)[/tex]

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