Answer :
Answer:x=-1
Step-by-step explanation:
To find this
We assume the number is x
The square of the number=x^2
Therefore when 5 is subtracted from the number we get
x^2-5=4× the number x
x^2-5=4x
X^2-4x-5
To factorise
x^2-5x+x-5
(x^2-5x)+(x-5)
x(x-5)+1(x-5)=0
(x+1)(x-5)=0
To find the negative solution
(x+1)=0or (x-5)=0
x=-1
Answer:
Step-by-step explanation
5 is subtracted from the square of a number
The square of a number is x with an exponent as 2
5 is then subtracted from the x with an exponent of 2
X^2 -5 is your answer