Answer :
Answer:
1287.5 N
Explanation:
We are given that
Mass of vehicle ,m=2100 kg
Weight of vehicle ,F=20,600 N
Area,A=[tex]0.56 cm^2=0.56\times 10^{-4} m^2[/tex]
[tex]1 cm^2=10^{-4} m^2[/tex]
We have to find the minimum force that must be applied to the attached piston of area [tex]0.035 cm^2[/tex] in order to lift the vehicle.
[tex]A'=0.035cm^2=0.035\times 10^{-4} m^2[/tex]
Apply the pascal's law
[tex]\frac{F}{A}=\frac{F'}{A'}[/tex]
[tex]\frac{20600}{0.56\times 10^{-4}}=\frac{F'}{0.035\times 10^{-4}}[/tex]
[tex]F'=\frac{20600}{0.56\times 10^{-4}}\times 0.035\times 10^{-4}=1287.5 N[/tex]